本文实例讲述了C#操作数据库中存取图片文件的方法。分享给大家供大家参考。具体如下:
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private string sqlconnstr = "Data Source=.;Database=db_test;User id=sa;PWD=123456" ; /*功能:把一种图片插入到数据库中 *返回值:无 */ void InsertImageToDB() { //将需要存储的图片读取为数据流 FileStream fs = new FileStream( @"D:/Bear.jpg" , FileMode.Open, FileAccess.Read); Byte[] byte_fs = new byte [fs.Length]; fs.Read(byte_fs, 0, Convert.ToInt32(fs.Length)); fs.Close(); //建立数据库连接 SqlConnection conn = new SqlConnection(sqlconnstr); conn.Open(); SqlCommand cmd = new SqlCommand(); cmd.Connection = conn; cmd.CommandText = "insert into tb_test(image_id,image_file) values(@image_id,@image_file)" ; SqlParameter[] param = new SqlParameter[2]; param[0] = new SqlParameter( "@image_id" , SqlDbType.Int); param[0].Value = 1; param[1] = new sqlParameter( "@image_file" , SqlDbType.Image); param[1].Value = byte_fs; for ( int index = 0; index < 2; index++) { cmd.Parameters.Add(param[i]); } //执行SQL语句 cmd.ExecuteNonQuery(); conn.Close(); } /*功能:从数据库中读取图像文件,并显示在PictureBox控件中 *返回值:无 */ void GetImageFromDB() { byte [] Data = new byte [0]; //建立数据库连接 SqlConnection conn = new SqlConnection(sqlconnstr); conn.Open(); SqlCommand cmd = new SqlCommand(); cmd.Connection = conn; cmd.CommandText = "select * from tb_parent" ; SqlDataReader sdr = cmd.ExecuteReader(); sdr.Read(); Data = ( byte [])sdr[ "parent_image" ]; //读取第一个图片的位流 MemoryStream mystream = new MemoryStream(Data); //用指定的数据流来创建一个image图片 System.Drawing.Image picbImage = System.Drawing.Image.FromStream(mystream, true ); mystream.Close(); picturebox1.Image = picbImage; conn.Close(); } |
希望本文所述对大家的C#程序设计有所帮助。