本文实例为大家分享了C语言实现双人五子棋游戏的具体代码，供大家参考，具体内容如下
实现功能
生成棋盘玩家1与玩家2对战，哪个玩家率先有连续5子连线，哪个玩家赢。
如何实现
组成：
二维数组：board[ROW][COL],定义一个ROW*COL的棋盘。
主要逻辑：
显示棋盘，提示用户下子，下子后判断
1.显示棋盘很简单，慢慢凑棋盘就好
2. 用户下子，注意两个条件：棋子在棋盘里，下子位置未被占用。
3.判断是最难的，
方法：从下子位置的8个方向(上，下，左，右，右上，右下，左上，左下)计算相同棋子数目，然后将对角的棋子数相加,等于5说明有5子连线
主要函数中用到三个主要实现函数：
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Showboard(board, ROW, COL)；//展示棋盘Playermove(board, ROW, COL, cur);//玩家下注，cur表示哪个玩家下子Judge(board, ROW, COL);//判断5子连线Getcount(board[][COL], row, col, dir)//计算方向dir相同棋子数 |
代码
头文件
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#ifndef __FIVECHREE_H__#define __FIVECHEE_H__#include<stdio.h>#include<windows.h>#pragma warning(disable:4996)#define ROW 10//棋盘行数#define COL 10//棋盘列数#define INIT '*'//棋盘初始化#define PLAYER1 1#define PLAYER2 2#define NEXT 3//继续往下下#define DRAW 4//棋盘下满 平局//8个方向#define UP 10#define RIGHT_UP 11#define RIGHT 12#define RIGHT_DOWN 13#define DOWN 14#define LEFT_DOWN 15#define LEFT 16#define LEFT_UP 17extern void Menu();extern void Game();#endif |
main函数源文件
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#include"fivechree.h"int main(){ int quit = 0; while (!quit){ Menu(); int select = 0; scanf("%d", &select); switch (select){ case 1: Game(); break; case 2: quit = 1; break; default: printf("Enter Error!\n"); break; } } printf("Byebye\n"); system("pause"); return 0;} |
函数定义源文件
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#include"fivechree.h"static int x = 0;static int y = 0;void Menu(){ printf("+---------------------+\n"); printf("+- 1.Play 2.Exit -+\n"); printf("+---------------------+\n"); printf("Please Enter Your Select#");}static void Showboard(int board[][COL], int row, int col){//展示棋盘 o玩家1棋子，x玩家2棋子 system("cls"); for (int i = 0; i < row; i++){ for (int j = 0; j < col; j++){ switch (board[i][j]){ case PLAYER1: board[i][j] = 'o'; break; case PLAYER2: board[i][j] = 'x'; break; case 0: board[i][j] = INIT; break; default: break; } } } printf(" "); for (int i =1; i <= row; i++){ printf("%2d ", i); } printf("\n"); for (int i = 1; i <= row; i++){ printf("%-2d", i); for (int j = 1; j <= col; j++){ printf(" %c ", board[i - 1][j - 1]); } printf("\n"); }}static void Playermove(int board[][COL], int row, int col, int who){//玩家下子，who 为哪个玩家下子 while (1){ printf("Please Enter PLAYER%d Postion<x,y>#", who); scanf("%d %d", &x, &y); if (x<1 || x>row || y<1 || y>col){ //超过棋盘范围 printf("Postion is error!\n"); continue; } if (board[x - 1][y - 1] == INIT){//判断位置是否已被下子 board[x - 1][y - 1] = who; break; } printf("Postion is not empty\n"); }}static int Getcount(int board[][COL], int row, int col, int dir){//判断8个方向相同棋子的数目 int _x = x;//_x,_y变化，后面与x，y棋子相比较 int _y = y; int count = 0; while (1){ switch (dir){ case UP: _x--; break; case DOWN: _x++; break; case LEFT: _y--; break; case RIGHT: _y++; break; case RIGHT_UP: _x--, _y++; break; case RIGHT_DOWN: _x++, _y++; break; case LEFT_DOWN: _x++, _y--; break; case LEFT_UP: _x--, _y--; break; default: break; } if (_x>=1 || _x<=row || _y>=1 || _y<=col){//棋子不能越界 if (board[x-1][y-1] == board[_x-1][_y-1]){ //printf("yes\n"); count++; } else{ //printf("no\n"); break; } } else{ return count; } } return count;}//如何判断：从下子位置的8个方向(上，下，左，右，右上，右下，左上，左下)//计算相同棋子数目，然后将对角的棋子数相加,等于5说明有5子连线static int Judge(int board[][COL], int row, int col){ int count1 = Getcount(board, row, col, UP)\ + Getcount(board, row, col, DOWN); //printf("%d\n", count1); if (count1 >= 4){ return board[x-1][y-1]; } count1 = Getcount(board, row, col, RIGHT_UP)\ + Getcount(board, row, col, LEFT_DOWN); //printf("%d\n", count1); if (count1 >= 4){ return board[x-1][y-1]; } count1 = Getcount(board, row, col, RIGHT)\ + Getcount(board, row, col, LEFT); //printf("%d\n", count1); if (count1 >= 4){ return board[x-1][y-1]; } count1 = Getcount(board, row, col, RIGHT_DOWN)\ + Getcount(board, row, col, LEFT_UP); if (count1 >= 4){ return board[x-1][y-1]; } for (int i = 0; i < row; i++){//判断棋盘是否下满 for (int j = 0; j < col; j++){ if (board[i][j] == INIT){ return NEXT; } } } return DRAW;}void Game(){ int board[ROW][COL] = { 0 }; //memset(board, INIT, ROW*COL); int result = 0; int cur = PLAYER1; Showboard(board, ROW, COL);//先展示棋盘 while (1){ //Showboard(board, ROW, COL); Playermove(board, ROW, COL, cur); Showboard(board, ROW, COL);//棋盘将board数组变化，所以要在判断前将数组变化 result = Judge(board, ROW, COL); if (result != NEXT){ break; } cur = (cur == PLAYER1 ? PLAYER2 : PLAYER1);//三目表达式，注意不是 PLAYER1 ? PLAYER2 : PLAYER1 } Showboard(board, ROW, COL); switch (result){ case 'o': printf("Player1 Win!\n"); break; case 'x': printf("Player2 Win!\n"); break; case DRAW: printf("Tie Game!\n"); break; default: //printf("%c\n", result); printf("BUG\n"); break; }} |
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/weixin_57023347/article/details/117463405
