C#实现字符串自增和自减运算，供大家参考，具体内容如下
1.数字从 0-9 变化；
2.字母从 A-Z、a-z 变化；
3.其它字符跳过；
4.以上变化依据其Ascii码值；
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/// <summary> /// 字符串运算 /// </summary> public class StringOperation { /// <summary> /// 通过ASCII码值，对字符串自增1 /// </summary> /// <param name="pStr">输入字符串</param> /// <returns></returns> public static string StringIncreaseOne(string pStr) { var vRetStr = pStr; if (0 == pStr.Length) { vRetStr = "1"; } else { // 将最后一个字符与之前的字符串分开 string vOtherStr = pStr.Substring(0, pStr.Length - 1); int vIntChar = (int)pStr[pStr.Length - 1]; //转ASCII码值 if (48 <= vIntChar && vIntChar <= 57) //是数字（0 - 9） { vIntChar++; //自增1 if (vIntChar == 58) // 进一位 { vIntChar = 48; vOtherStr = StringIncreaseOne(vOtherStr); } } else if (65 <= vIntChar && vIntChar <= 90) //是字母（A - Z） { vIntChar++; //自增1 if (vIntChar == 91) { vIntChar = 65; vOtherStr = StringIncreaseOne(vOtherStr); } } else if (97 <= vIntChar && vIntChar <= 122) //是字母（a - z） { vIntChar++; //自增1 if (vIntChar == 123) { vIntChar = 97; vOtherStr = StringIncreaseOne(vOtherStr); } } else // 其它字符 -> 跳过 { vOtherStr = StringIncreaseOne(vOtherStr); } vRetStr = vOtherStr + (char)vIntChar; } return vRetStr; } /// <summary> /// 通过ASCII码值，对字符串自减1 /// </summary> /// <param name="pStr">输入字符串</param> /// <returns></returns> public static string StringReducingOne(string pStr) { var vRetStr = pStr; if (0 == pStr.Length) { vRetStr = "9"; } else { string vOtherStr = pStr.Substring(0, pStr.Length - 1); int vIntChar = (int)pStr[pStr.Length - 1]; //转ASCII码值 if (48 <= vIntChar && vIntChar <= 57) //是数字（0 - 9） { vIntChar--; if (vIntChar == 47) { vIntChar = 57; vOtherStr = StringReducingOne(vOtherStr); } } else if (65 <= vIntChar && vIntChar <= 90) //是数字（A - Z） { vIntChar--; if (vIntChar == 64) { vIntChar = 90; vOtherStr = StringReducingOne(vOtherStr); } } else if (97 <= vIntChar && vIntChar <= 122) //是数字（a - z） { vIntChar--; if (vIntChar == 96) { vIntChar = 122; vOtherStr = StringReducingOne(vOtherStr); } } else // 其它字符 -> 跳过 { vOtherStr = StringReducingOne(vOtherStr); } vRetStr = vOtherStr + (char)vIntChar; } return vRetStr; } /// <summary> /// 通过ASCII码值，对字符串自增 /// </summary> /// <param name="pStr">输入字符串</param> /// <param name="pCount">自增个数</param> /// <returns></returns> public static string StringIncrease(string pStr, int pCount) { string vRetStr = pStr; for (int i = 0; i < pCount; i++) { vRetStr = StringIncreaseOne(vRetStr); } return vRetStr; } /// <summary> /// 通过ASCII码值，对字符串自减 /// </summary> /// <param name="pStr">输入字符串</param> /// <param name="pCount">自减个数</param> /// <returns></returns> public static string StringReducing(string pStr, int pCount) { string vRetStr = pStr; for (int i = 0; i < pCount; i++) { vRetStr = StringReducingOne(vRetStr); } return vRetStr; } } |
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原文链接：http://www.cnblogs.com/CUIT-DX037/p/6770535.html
