openCV实现将图像切成m*n块，供大家参考，具体内容如下
一、代码部分：
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#include "stdafx.h"#include <opencv2/core/core.hpp>#include <opencv2/highgui/highgui.hpp>#include <iostream> #include <vector> #include<string>#include<sstream>using namespace std;using namespace cv;//Cut an image into m*n patchvoid Cut_img(Mat src_img, int m, int n, vector<Mat> ceil_img){ int t = m * n; int height = src_img.rows; int width = src_img.cols; int ceil_height = height / m; int ceil_width = width / n; Mat roi_img; //String concatenation ostringstream oss; string str, str1, str2; Point p1, p2; for (int i = 0; i<m; i++) { for (int j = 0; j<n; j++) { Rect rect(j*ceil_width, i*ceil_height, ceil_width, ceil_height); src_img(rect).copyTo(roi_img); ceil_img.push_back(roi_img); oss << i; str1 = oss.str(); oss.str(""); oss << j; str2 = oss.str(); oss.str(""); str = "roi_img_" + str1 + "_" + str2; imshow(str, roi_img); IplImage *ipl_roi_img=&IplImage(roi_img); //save processed img char tmp[100]="\0"; sprintf(tmp,"..\\post_img\\71253_%d_%d.jpg",i,j); cvSaveImage(tmp,ipl_roi_img); } }}int _tmain(int argc, _TCHAR* argv[]){ char *img_name_path="..\\image\\71253.jpg"; Mat img = imread(img_name_path,1); imshow("src_img", img); waitKey(0); int m = 2; int n = 2; vector<Mat> ceil_img ; Cut_img(img, m, n, ceil_img); cvWaitKey(0); return 0;} |
二、程序运行结果：
（1）原图像：
（2）切割后图像：
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/lindamtd/article/details/75194993
