采用二维数组制作五子棋，用坐标下棋。
请看代码。
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include<stdio.h>#include<string.h>#include<stdlib.h>#include<windows.h>#include<conio.h>#include<time.h> void menu()//目录{ char xuanze = 0,xuanze2; printf("\n"); printf("\n"); printf(" #############################################\n"); printf(" *五子棋小游戏*\n"); printf(" *1.双人游戏*\n"); printf(" *2.人机对战（暂未开放）\n"); printf(" *3.游戏须知\n"); printf(" #############################################\n"); printf(" 请选择选项，目前仅有 1 选项\n"); printf("\n"); printf(" "); xuanze = _getch(); switch (xuanze) { case 1: break; case 3: printf("本游戏是键盘输入坐标来落子的，白棋先落，第二次落子为黑色，依次落子。\n"); printf("若落子坐标非法则需重新落子。\n"); printf("键盘输入1直接进入游戏\n"); }}int t = 2;int pan[20][20] ={ {1,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,3}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {7,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,9}};void qp()//棋盘{ int i, j, k = 0; printf(" "); for (i = 0; i < 10; i++) printf(" %d", i + 1); for (i = 10; i < 20; i++) printf("%d", i + 1); printf("\n"); printf("1 "); //printf("┌ ┬ ┐├ ┼ ┤└ ┴ ┘│ ");©○●┼ for (i = 0; i < 20; i++) for (j = 0; j < 20; j++) { switch (pan[i][j]) { case 1: printf("┌ "); k++; if (k % 20 == 0) { printf("\n"); } break; case 2: printf("┬ "); k++; if (k % 20 == 0) printf("\n"); break; case 3: printf("┐ "); k++; if (k % 20 == 0) { printf("%d", i+1); printf("\n"); printf("%d ", i + 1); } break; case 4: printf("├ "); k++; if (k % 20 == 0) printf("\n"); break; case 5: printf("┼ "); k++; if (k % 20 == 0) printf("\n"); break; case 6: printf("┤ "); k++; if (k % 20 == 0) { printf("%d", i+1); printf("\n"); if(i<8) printf("%d ", i + 2); if(i>7) printf("%d", i + 2); } break; case 7: printf("└ "); k++; if (k % 20 == 0) printf("\n"); break; case 8: printf("┴ "); k++; if (k % 20 == 0) printf("\n"); break; case 9: printf("┘ "); k++; if (k % 20 == 0) { printf("%d", i + 1); printf("\n"); } break; case 10: printf("○"); k++; if (k % 20 == 0) { printf("%d", i+1); printf("\n"); } break; case 11: printf("●"); k++; if (k % 20 == 0) { printf("%d", i+1); printf("\n"); } break; } } printf(" "); for (i = 0; i < 10; i++) printf(" %d", i + 1); for (i = 10; i < 20; i++) printf("%d", i + 1); printf("\n"); printf("\n");}void play(){ int i, j; while (1) { printf("*请选择落子坐标(x,y): "); scanf_s("%d %d", &j, &i); printf("\n"); if(i>0&&i<21&&j>0&&j<21) { if (pan[i - 1][j - 1] != 10 && pan[i - 1][j - 1] != 11) { if (t % 2 == 1) { t++; pan[i - 1][j - 1] = 11; break; } else if (t % 2 == 0) { t++; pan[i - 1][j - 1] = 10; break; } } else if (pan[i-1][j-1] == 10 || pan[i-1][j-1] == 11) { printf("此处已经有棋子，请重新输入\n"); continue; } } else if (i < 1 || i > 21 || j < 1 || j > 21) { printf("坐标不合法，请重新输入\n"); continue; } } }void test(){ int i, j; for(i=0;i<20;i++) for (j = 0; j < 20; j++) { if (pan[i][j] != 1 || 2 || 3 || 4 || 5 || 6 || 7 || 8 || 9) { if (pan[i][j] == pan[i][j + 1]&&pan[i][j] == pan[i][j + 2]&&pan[i][j] == pan[i][j + 3]&&pan[i][j] == pan[i][j + 4]) { if (pan[i][j] == 11) { printf("白棋获胜\n"); } if (pan[i][j] == 10) { printf("黑棋获胜\n"); } } if (pan[i][j] == pan[i + 1][j]&&pan[i][j] == pan[i + 2][j]&&pan[i][j] == pan[i + 3][j]&&pan[i][j] == pan[i + 4][j]) { if (pan[i][j] == 11) { printf("白棋获胜\n"); } if (pan[i][j] == 10) { printf("黑棋获胜\n"); } } if (pan[i][j] == pan[i + 1][j + 1]&&pan[i][j] == pan[i + 2][j + 2]&&pan[i][j] == pan[i + 3][j + 3] &&pan[i][j]== pan[i + 4][j + 4]) { if (pan[i][j] == 11) { printf("白棋获胜\n"); } if (pan[i][j] == 10) { printf("黑棋获胜\n"); } } if (pan[i][j] == pan[i - 1][j + 1]&&pan[i][j] == pan[i - 2][j + 2] &&pan[i][j]== pan[i - 3][j + 3]&&pan[i][j] == pan[i - 4][j + 4]) { if (pan[i][j] == 11) { printf("白棋获胜\n"); } if (pan[i][j] == 10) { printf("黑棋获胜\n"); } } } }}int main(){ system("mode con cols=98 lines=48"); SetConsoleTitleA("五子棋小游戏"); //设置窗口 menu(); system("cls"); while (1) { qp(); test(); play(); system("cls"); } system("pause"); return 0;} |
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原文链接：https://blog.csdn.net/may10/article/details/109448197
